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- Apr 18, 2013
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- Mantis Toboggan, MD
Disproof by example: In a flat turn (wings level skidding turn) with the same turn rate as the illustration the centripetal acceleration and gravity will be the same values presented in the drawing, but lift will be equal to weight, *normal* acceleration (vertical WRT the airplane) will be zero, and the load factor 1g. Simple to demonstrate if you have an accelerometer in your airplane.What am I missing? It is 65 years since I studied this, so may have forgotten something...
Turn the airplane in the illustration upside down and consider an inverted ('outside') turn at the same conditions. The math works the same, giving the same result as the example, but the true load factor on the airplane will be negative.
Symmetric lift causes normal acceleration, lift divided by weight is load factor.
and neither centrifugal nor centripetal *force* are measured in g's as shown in the drawing.You guys are missing the myth. In a fixed reference frame, centrifugal force is a fictional force; what really occurs is centripetal force.
Nauga,
who has been framed
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