Half Fast
Touchdown! Greaser!
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- May 7, 2016
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- Central Florida
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If P is .5 how can you end up with a greater than 100% chance? [(2*.5) + .25] You can't. Well, evidently YOU can.
Going past 50%, you're saying there's a more than 200% chance that something will occur if the probabilities are 75% for each one.
.75 + .75 + .5625
Recheck your math.
Ed, if you'd learn a little math, you might have noticed that I made a sign error. The correct equation is 2P - P^2 and I've corrected my post above. It does NOT change my conclusion that a twin is twice as likely to have an engine failure as a single, a statement that you called "bad math." In the case of engine failures, P is a small number and the P^2 term becomes insignificant for the quality of our data.
In the coin example you seem to like, 2P - P^2 = 2(0.5) - (0.5^2) = 0.75. In the case of larger values of P, such as P=0.5, the P^2 term is not insignificant.
BOTTOM LINE - a twin is indeed twice as likely to experience an engine failure as a single. You have said that is "bad math" but you have yet to show "good math" that justifies a different conclusion.