Yoke deflection, load factor & stall

Richard_SWave

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Rich_Swave
A small airplane always stalls when you pull back on the yoke and your airspeed is below Va?

Or is it possible that at some speeds to not have enough elevator authority to reach the G for the accelerated stall? Basically, can you pull back on the stick (especially the case you pull full back) without having an accelerated stall?

Please pay attention to my assumption here: for example, a Cessna stalls at 2G at 66 kts. A full back yoke will produce 2G at 66 kts? As an example, always a 80% yoke aft deflection produces 80% of the stall load factor?

I figured out that in some Cessnas at some speeds below Va you can pull back on the stick, you feel the G, but the aircraft doesn’t stall immediately but just seconds after that when the airspeed decreases enough. Is this right or I noticed it wrong?

Also, at some speeds I think you can deflect let’s say 80% aft yoke without accelerated stall, but I figured out not at all.

What I know is that an aircraft can be stalled at any speed and attitude. All it matters is angle of attack, however, this doesn’t help me too much to figure out my problem.

Thank you very much!
 
A small airplane always stalls when you pull back on the yoke and your airspeed is below Va?
Whether it stalls or not depends on how hard you pull the yoke, but what being below Va guarantees is that the plane will stall before you put enough g-load on the plane to break anything.

Or is it possible that at some speeds to not have enough elevator authority to reach the G for the accelerated stall? Basically, can you pull back on the stick (especially the case you pull full back) without having an accelerated stall?
Absolutely. Keep in mind that the term "accelerated stall" means a stall which occurs at a speed higher than the "normal" 1g stall speed. If you just pull the throttle back to idle, and keep the plane from descending by increasing angle of attack to keep lift equal to weight as the airplane decelerates, an unaccelerated stall will occur at "normal" stall speed with only 1 g on the plane.

However, if you are just flying along in cruise just below Va and abruptly put full back yoke on the plane, you will put a pretty good g-load on the plane and the plane will stall at a much higher than normal stall speed with more than 1g in what is called an "accelerated stall." Finally, if you are cruising above Va and make that same abrupt full back yoke input, you may exceed the allowable g-load before the plane reaches the stalling angle of attack, and that is when you can bend or break something.

Please pay attention to my assumption here: for example, a Cessna stalls at 2G at 66 kts. A full back yoke will produce 2G at 66 kts?
No. It will depend on how rapidly you pull the yoke back. If you make an abrupt pull, you'll probably reach 2g's and the stall simultaneously, but if you make a slow pull, the plane will decelerate to a lower speed before reaching stalling angle of attack, and then it will stall at a lower speed and lower g-load.

As an example, always a 80% yoke aft deflection produces 80% of the stall load factor?
The relationship between yoke position and g-load is not linear.

I figured out that in some Cessnas at some speeds below Va you can pull back on the stick, you feel the G, but the aircraft doesn’t stall immediately but just seconds after that when the airspeed decreases enough. Is this right or I noticed it wrong?
It's all about how abruptly you pull the yoke back.
 
If you make an abrupt pull, you'll probably reach 2g's and the stall simultaneously, but if you make a slow pull, the plane will decelerate to a lower speed before reaching stalling angle of attack, and then it will stall at a lower speed and lower g-load.

The relationship between yoke position and g-load is not linear.

It's all about how abruptly you pull the yoke back.
So, I figure out there is usually enough elevator authority at any speed to stall the airplane accelerated if I abruptly pull back on the yoke, right?

I don't know why on a Cessna 172 I felt that at some speeds full aft yoke won't reach the necessary Gs to stall it.

Also, the fact that the relationship between yoke position and g-load is not linear seems a little bit opposing.
 
So, I figure out there is usually enough elevator authority at any speed to stall the airplane accelerated if I abruptly pull back on the yoke, right?

I don't know why on a Cessna 172 I felt that at some speeds full aft yoke won't reach the necessary Gs to stall it.

Also, the fact that the relationship between yoke position and g-load is not linear seems a little bit opposing.

Does the airplane stall when sitting on the ground and you yank the yoke fully aft? Or while taxiing?

Stall is directly related to AoA. Not airspeed. Not elevator authority. Not G loads. Angle of Attack. That's it. Exceed the critical AoA, and you stall.

Why isn't it linear? Solve for y:

y = mxp + nx +b

What? You can't? Oh yeah, because there's too many variables. Same with yoke position, load factor, and airspeed.
 
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So, I figure out there is usually enough elevator authority at any speed to stall the airplane accelerated if I abruptly pull back on the yoke, right?
At least below Va, yes, that is generally true, although the closer you are to 1-g stall speed when you start the pull, the less acceleration you'll be able to develop before the stall occurs. Above Va, you may have the wings rip off before they stall. :eek:

I don't know why on a Cessna 172 I felt that at some speeds full aft yoke won't reach the necessary Gs to stall it.
:dunno: Perhaps that will change with more flight experience.

Also, the fact that the relationship between yoke position and g-load is not linear seems a little bit opposing.
Not sure what you mean by that. If you get into the aerodynamics books, you'll see why it is the way it is, but it's a little more complicated than I have finger stamina to explain here.
 
Something like if I pull abruptly the yoke 3/4 aft at 70 kts, it stalls. If I do the same thing at 90 kts, it doesn't. Both are below Va.

Is this false?
 
Something like if I pull abruptly the yoke 3/4 aft at 70 kts, it stalls. If I do the same thing at 90 kts, it doesn't. Both are below Va.

Is this false?

Undefined. Not enough information to answer the question.
 
Not enough information to answer the question.

Could you please write at least some of the information required to figure it out? Which are the factors involved? Thank you very much!
 
Could you please write at least some of the information required to figure it out? Which are the factors involved? Thank you very much!

What's your angle of attack? That's the only question that needs to be answered.
 
Ok, so I understand it is hard to figure out the angle of attack and you can't predict it and there's no general rule to aproximate how it will behave in that situation.
 
Ok, so I understand it is hard to figure out the angle of attack and you can't predict it and there's no general rule to aproximate how it will behave in that situation.

Have you had calculus? It's a calculus problem.
 
I feel you are somehow playing a little bit with me. There is a difference between hard to be predictable or not known because it was not analyzed. What I understand first from your posts is that it's hard to predict it.
 
I feel you are somehow playing a little bit with me. There is a difference between hard to be predictable or not known because it was not analyzed. What I understand first from your posts is that it's hard to predict it.

It's not hard to predict, you just have about 4 variables that affect the outcome. Change any one of those, and the result changes. It's not a 2+x=4 equation where you solve for x.

Your question is like asking how heavy is a rock?
 
So, I figure out there is usually enough elevator authority at any speed to stall the airplane accelerated if I abruptly pull back on the yoke, right?

Under normal conditions on a 172, you won't run out of elevator authority prior to the stall, but you can with abnormal conditions, such as structural icing or excessively forward CG.

Even worse, under those conditions, the elevator can stall prior to the wing. Really bad situation.
 
Welcome to POA

You are thinking way too hard. :lol:

Amen....You're making my hair hurt....

Angle of Attack/thats all you really need to know. Va is a limitation based on the structural capability of the aircraft. All the other factors have virtually an infinite number of variables. As was explained, its not a linear relationship.
 
I asked you above to name them. I would appreciate it.

rate of change in vertical speed
rate of change in pitch
rate of change in yaw
rate of change in roll
rate of change in airspeed
rate of change in load factor

All of these go into changing the AoA and stall speed

When the AoA is around 17 degrees the wing stalls.

What is the reasoning behind your question?
 
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The reason is that based on some practical observations I wonder if there's possible to yank the yoke back in some airplanes and not stalling the wing and also not overstressing the airframe considering not achieving max positive load. Don't worry, I'm not going to do it too soon, otherwise I wouldn't ask it, I will try.
 
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Ric[U said:
hard_SWave;1074341]Ok, so I understand it is hard to figure out the angle of attack and you can't predict it and there's no general rule to aproximate how it will behave in that situation.
Unfortunately I think you're looking for a simple answer to a complicated (and somewhat ill formed) question but perhaps we can clear things up a bit with some related basics. Ed is correct that the one thing that's most consistent with stalling is the wing's angle of attack. It's also true that AoA isn't necessarily easy to visualize or understand and IMO pilot training has been a bit too vague about the subject.

First let's consider things from a static perspective (your reference to pulling back abruptly on the yoke introduces dynamics that add considerable complexity). If you were to draw a curve of AoA vs lift coefficient (the amount of lift generated for a particular calibrated airspeed) you would see something that looks like a hill with a curved top and typically a steeper slope on the "back" (greater AoA) side of the hill. The top of the "hill" represents the maximum coefficient of lift the wing can achieve and the AoA where that occurs. This is called the "critical" AoA and is the AoA at which the wing stalls. Also typical but not necessarily always true is that the front side is fairly linear from below the origin ("zero lift AoA") up to 70-80% of the critical AoA point.

Another relevant curve plots CAS vs AoA for a constant amount of lift (e.g. the weight of the airplane in unaccelerated flight). This one looks somewhat like an inverted copy of CoL but since lift is proportional to the square of CAS and therefore for the linear portion of the first curve CAS is
proportional to 1/SQRT(AoA), the left end goes to infinity (infinite CAS is needed to genearate lift at the zero lift AoA) and the curve looks more like an inverted parabola.

If you are in level flight in smooth air your AoA has a fixed linear relationship to the airplane's pitch attitude with the difference being the angle between whatever you consider "zero pitch" and the chord line of the wing (often called the "angle of incidence"). If you start at your maximum speed for level flight and slow the airplane very gradually to point where a stall begins your AoA and the corresponding pitch attitude will follow the second curve described above.

Finally, because the amount of lift (and hence the g-force) for a give AoA is directly proportional to the square of CAS, the change in the CAS at the critical AoA is equal to the square of the g force.

It's also generally true that the elevator and stick/yoke position has a fixed relationship to AoA under static conditions (i.e. the AoA that exists when the elevator position has been constant long enough for things to stabilize) although this is also affected by the airplane's gross weight and CG.

Now to try an answer your original questions:

A small airplane always stalls when you pull back on the yoke and your airspeed is below Va?
Assuming you're asking if this is true or false, the most succinct answer would be no. A stall will eventually be generated if you pull the yoke far enough back and hold it there long enough so that the airplane's wing reaches the critical AoA. If the yoke movement is applied slowly enoug.h that the critical AoA is reached while the g force is 1 then the stall will occur when the plane has slowed to the same CAS which generates a stall in level flight, i.e. when the power is reduced and altitude is maintained (note: this is ignoring the small contribution to lift from the propeller thrust). OTOH, if you go to the opposite extreme moving the elevator as rapidly as possible the wing will stall almost immediately with virtually no change in CAS. I say almost because the airplane will still have to rotate about the lateral axis (i.e. the pitch angle must go up) and that always takes some time, during which the airspeed will drop slightly due to the increased drag. Also note that some airplanes don't have enough elevator authority to achieve the wing's critical AoA (e.g. Ercoupe) and any airplane lacks that ability if the CG is far enough forward (typically beyond the approved envelope).

Or is it possible that at some speeds to not have enough elevator authority to reach the G for the accelerated stall? Basically, can you pull back on the stick (especially the case you pull full back) without having an accelerated stall?
Off the top of my head I'd say that if there's enough authority to stall in unaccelerated flight then there will be enough authority to stall at Va. The ability of the elevator to generate downforce is (like most things related to lift) proportional to the square of the CAS and the force required to affect any change in AoA is likely also proportional to the square of the CAS. Note that the force you must apply to the yoke to alter the AoA also increases with CAS in most airplanes.

Please pay attention to my assumption here: for example, a Cessna stalls at 2G at 66 kts. A full back yoke will produce 2G at 66 kts?
Not necessarily. I'm assuming that you're talking about 66 Kts CAS not IAS and that this is at a constant (likely max GW) weight (CAS diverges from IAS at high AoA so we must use CAS here). As described already, the airplane's behavior is going to depend on your initial CAS, the CG, and how rapidly you move the yoke. Clearly if you move it gradually you will never get anywhere near 2G but even if you yank it as quickly as you can it's not likely you'll reach 2G before the wing stalls because the airplane will slow down some before the critical AoA is reached.

As an example, always a 80% yoke aft deflection produces 80% of the stall load factor?
Definitely not true. As mentioned earlier for a specific CG and weight the yoke position will have a relatively constant relationship with AoA under static conditions but while the yoke is moving and/or the airplane is changing airspeed that relationship goes out the window. In addition, while static elevator position does relate well to AoA, there's no such relationship between elevator position and G load unless you can somehow hold CAS constant.

I figured out that in some Cessnas at some speeds below Va you can pull back on the stick, you feel the G, but the aircraft doesn’t stall immediately but just seconds after that when the airspeed decreases enough. Is this right or I noticed it wrong?
Sounds correct for any airplane.

Also, at some speeds I think you can deflect let’s say 80% aft yoke without accelerated stall, but I figured out not at all.
I'm not sure what that is intended to mean.

What I know is that an aircraft can be stalled at any speed and attitude. All it matters is angle of attack, however, this doesn’t help me too much to figure out my problem.
If all airplanes had an AoA indicator (BTW one of mine does) and pilots were taught to reference that instead of IAS to predict stalls you'd probably find this a lot easier to understand. It's too bad someone decided a long time ago to mark a dynamic pressure gauge with numbers representing the airspeed required to achieve that dynamic pressure in a standard atmosphere at zero MSL. If instead, they had just used a pressure scale (e.g. PSI, KPa, etc) for that instrument and added an AoA indicator there'd probably be a lot less concern about stall "speed" and instead of Va, Vfe, and Vne we'd be taught about Pa, Pfe, and Pne and allowing pilots to ignore the complicated relationship bewteen stall behavior and dynamic pressure.
 
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First, I would like to thank you for your detailed explanations, I really appreciate. However, I have some doubts.

Also note that some airplanes have enough elevator authority to achieve the wing's critical AoA (e.g. Ercoupe)
And some not? I thought all do. Is the Cessna 172 case? This is particulary important cause it addresses some of my doubts.

My post here: Also, at some speeds I think you can deflect let’s say 80% aft yoke without accelerated stall, but I figured out not at all. I'm not sure what that is intended to mean.
I meant you might be able to slam the yoke 2/3 back at some speeds and not results an almost instant stall.

EDIT: I will also address a problem which I don't have practical experience with. Why are some airplanes (I think aerobatic planes) more likely to have a hard wingover if you pull hard on yoke and have an accelerated stall? Is the fact that they get more uncoordinated when you pitch up? Or is there a design factor? I figure out this won't happen if the pilot kept it perfectly coordinated, right?
 
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First, I would like to thank you for your detailed explanations, I really appreciate. However, I have some doubts.


And some not? I thought all do. Is the Cessna 172 case? This is particulary important cause it addresses some of my doubts.
My bad. I meant to write "some airplanes don't have enough.." and I corrected that mistake now. I'm pretty sure any C-172 that's within the published CG limits has enough elevator authority to stall the wing at any speed below Va. OTOH, it's quite likely that the official W&B data for some 172s has enough error that one might appear to be at the forward CG limit when it's actually far enough out to prevent a full stall. But odds are the one(s) you are flying are not on that list.

I meant you might be able to slam the yoke 2/3 back at some speeds and not results an almost instant stall.
I can't speak to what "2/3rds back" will do but you should be able to get a "clean break" if you yank the wheel back abruptly all the way. And I believe that if you pull back to the same position (plus a little more) that causes a stall at 1g the plane will eventually stall no matter how rapidly you pull it back.

I will also address a problem which I don't have practical experience with. Why are some airplanes (I think aerobatic planes) more likely to have a hard wingover if you pull hard on yoke and have an accelerated stall? Is the fact that they get more uncoordinated when you pitch up? Or is there a design factor? I figure out this won't happen if the pilot kept it perfectly coordinated, right?
First, a lot depends on whether the airplane (and particularly the wing) was designed for benign stall characteristics. Most "modern" GA airplanes have wings that will maintain aileron effectiveness into a stall. Typically this is accomplished by "washing out the wing" i.e. reducing the wing's angle of incidence gradually from root to tip. That makes the roots stall at a lower average AoA than the tips so you lose lift without losing roll control. Cirrus took a slightly different approach to this and actually used two different wing cross sections for the inner and outer portions of the wing. Another wing design characteristic is how sharply the stall "breaks" and this is reflected in the shape of the C of L vs AoA curve. A laminar flow wing like you see on a SF-260 (http://en.wikipedia.org/wiki/Aermacchi_SF.260) and many fast homebuilts has very sharp "pointed" top of that curve vs a 172's curve which has a fairly broad shallow curve on the top. With a sharp curve a very small change in AoA produces a very large decrease in lift (coupled with a large increase in drag) and as you might expect a shallow curve top just feels "mushy" near the stalling AoA, especially when combined with plenty of washout.


Finally there's the issue of aileron position vs asymmetrical drag which causes adverse yaw (what makes an airplane turn right initially when you roll to the left). A 172's ailerons are connected so that the one going down has less angle change from level than the one going up and this somewhat cancels the extra drag on the side of the down aileron due to the extra lift it creates (i.e induced drag). There are other factors like dihedral, fuselage shape, engine power/torque and more that also have some effect on this as well.

If you combine all of that you can make an airplane that requires a lot of rudder input during a stall to keep the plane from rolling and/or yawing vs one that pretty much always stalls straight ahead even if the pilot attempts to raise a dropping wing with aileron input. But either one can be stalled without much fanfare as long as you start out coordinated and then maintain yaw and roll control with the rudder.

BTW it can be difficult to maintain "coordination" into a stall. Things like engine torque, P-factor, and rigging all contribute to asymmetries in the lift and AoA of each wing.
 
First, a lot depends on whether the airplane (and particularly the wing) was designed for benign stall characteristics. Most "modern" GA airplanes have wings that will maintain aileron effectiveness into a stall. Typically this is accomplished by "washing out the wing" i.e. reducing the wing's angle of incidence gradually from root to tip. That makes the roots stall at a lower average AoA than the tips so you lose lift without losing roll control. Cirrus took a slightly different approach to this and actually used two different wing cross sections for the inner and outer portions of the wing. Another wing design characteristic is how sharply the stall "breaks" and this is reflected in the shape of the C of L vs AoA curve. A laminar flow wing like you see on a SF-260 (http://en.wikipedia.org/wiki/Aermacchi_SF.260) and many fast homebuilts has very sharp "pointed" top of that curve vs a 172's curve which has a fairly broad shallow curve on the top. With a sharp curve a very small change in AoA produces a very large decrease in lift (coupled with a large increase in drag) and as you might expect a shallow curve top just feels "mushy" near the stalling AoA, especially when combined with plenty of washout.


Finally there's the issue of aileron position vs asymmetrical drag which causes adverse yaw (what makes an airplane turn right initially when you roll to the left). A 172's ailerons are connected so that the one going down has less angle change from level than the one going up and this somewhat cancels the extra drag on the side of the down aileron due to the extra lift it creates (i.e induced drag). There are other factors like dihedral, fuselage shape, engine power/torque and more that also have some effect on this as well.

If you combine all of that you can make an airplane that requires a lot of rudder input during a stall to keep the plane from rolling and/or yawing vs one that pretty much always stalls straight ahead even if the pilot attempts to raise a dropping wing with aileron input. But either one can be stalled without much fanfare as long as you start out coordinated and then maintain yaw and roll control with the rudder.

BTW it can be difficult to maintain "coordination" into a stall. Things like engine torque, P-factor, and rigging all contribute to asymmetries in the lift and AoA of each wing.
And all those factors are the same for an inverted stall, right? Or for an inverted doesn't have this tendency to wingover?

If I PUSH all the yoke in a C172 I haven't seen a noticeable tendency which might seem like a stall.
 
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A small airplane always stalls when you pull back on the yoke and your airspeed is below Va?
Not necessarily. A Piper Colt doesn't stall if you gradually apply back pressure with idle power in level flight even after the elevator stop is hit. Adding power makes the elevator efficient enough to cause a stall. Or you can raise the nose high and try to keep it there. When you run out of elevator--the nose drops causing an increase in AoA and a stall.

Or is it possible that at some speeds to not have enough elevator authority to reach the G for the accelerated stall? Basically, can you pull back on the stick (especially the case you pull full back) without having an accelerated stall?
Yes, but I don't like the way you think of "g". Here's the way it works: Elevator controls AoA. AoA deflects the flight path, or at least tries. If the flight path is straight, the only "g" is gravity. If it's an upward curve, like entering a loop, "g's" are the sum of gravity and centrifugal force. At the bottom, they add; floating over the top, gravity is subtracted. So, "g" force depends on the orientation of gravity. A banked turn is a loop in an oblique plane where the gravitational offset against centrifugal force is established by trigonometry.

In a steep bank, the tail on a Cessna 172 at slow speeds is way out back behind the CG which is tangent to the turn's flight path. This means the local airflow strikes the elevator more from below than in straight and level flight, robbing it of authority. It's less capable of causing a stall, even though it may, but the yoke will be further back. The loss of authority can be replaced with additional power.

I figured out that in some Cessnas at some speeds below Va you can pull back on the stick, you feel the G, but the aircraft doesn’t stall immediately but just seconds after that when the airspeed decreases enough. Is this right or I noticed it wrong?
I'd say you "ran out of elevator", but since the nose was up it stalled as it started to fall.

dtuuri
 
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This means the local airflow strikes the elevator more from below than in straight and level flight, robbing it of authority. It's less capable of causing a stall, even though it may, but the yoke will be further back.

dtuuri
Interesting, I figure out if you don't have enough authority in an emergency (too aft CG, elevator control problem etc.) to avoid a stall, you might be more able to handle it somehow banking hard, maybe toward a knife edge attitude, or I'm entirely wrong?
 
Interesting, I figure out if you don't have enough authority in an emergency to avoid a stall, you might be able to handle it somehow banking hard, maybe toward a knife edge attitude, or I'm entirely wrong?
I don't follow that logic at all. All you have to do to avoid a stall is let go.

dtuuri
 
My brain hurts. Ed is 100% right - take speed, G force, altitude, and anything else out of the equation. The ONLY thing that causes an airplane to stall is AOA - either positive or negative.

You could load 50 Gs on the wings at 3 degrees of AOA, and while you may rip the wings off, you wouldn't stall (until the wings fell off...at that point, you'd have an AOA of approximately 90 degrees since the wing would be the plane itself).

The question you are asking doesn't matter....you may or may not have the elevator authority to pull Gs, or to break the critical angle of attack. To determine whether you have the authority or not, you'd need an equation that takes every variable into account - TAS, IAS, altitude, current AOA, full travel length of the yoke, available travel length of the yoke before the yank, etc.
 
I don't follow that logic at all. All you have to do to avoid a stall is let go.

dtuuri
Let go what? I said if you don't have authority, let's say the elevator jammed or the CG is too aft.
 
Let go what? I said if you don't have authority, let's say the elevator jammed or the CG is too aft.

Even though I suspect this is an example of reducto ad absurdium, one possible solution if its a power-on stall would be to remove power and wait. The plane's AOA may naturally decrease as power went down.

Or maybe try the elevator trim or something.

This might be the situation where you just sit on your hands and start calling ATC to relay messages to your loved ones for you.
 
Let go what? I said if you don't have authority, let's say the elevator jammed or the CG is too aft.
Let go of the yoke. The plane doesn't want to stall, you need to force it. You need to have enough elevator, wait for it... A_U_T_H_O_R_I_T_Y. If you don't have enough, it can't stall. Or, if you aren't strong enough to pull the yoke back far enough.

If the elevator is jammed where? Unless you got it stuck in the full aft position or nearly so, you aren't stalled. I'd be more concerned about having your trim stuck. That's something you can fix. If you need to push the yoke you'll want to enter a bank to keep the nose down, so you don't enter into an unsustainable climb leading to a stall. After you get the airspeed down and maybe enter the landing configuration that matches the amount of nose-up trim you're stuck with you can level the wings and head slowly for an airport.

If the CG is too far aft, you didn't do a weight and balance before departure or your cargo shifted. Sorry, can't help you there.

dtuuri
 
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If the elevator is jammed where? Unless you got it stuck in the full aft position or nearly so, you aren't stalled. I'd be more concerned about having your trim stuck. That's something you can fix. If you need to push the yoke you'll want to enter a bank to keep the nose down, so you don't enter into an unsustainable climb leading to a stall.

dtuuri
If the elevator is jammed towards aft, not necessary full aft, you'll also enter into an unsustainable climb leading to a stall. So, why do you think only about the trim?
And even in the trim case, I doubt you'll be able to overcome if its close to its extreme positions.
 
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If the elevator is jammed towards aft, not necessary full aft, you'll also enter into an unsustainable climb leading to a stall. So, why do you think only about the trim?
I think of 'authority' in terms of forcing an increased angle of attack. You apparently think of it in absolute terms, as in unable to have any effect at all. The issue of jammed controls is different from what I'm addressing. I'd rather not go there in any more detail, since it clouds what I believe are the most important lessons to be learned from your accurate observations of stall behavior that many others may have been wondering about too.

I'm done.

dtuuri
 
When you run out of elevator--the nose drops causing an increase in AoA and a stall.
You lost me there. The nose drops and increases AOA?

Yes, but I don't like the way you think of "g". Here's the way it works: Elevator controls AoA. AoA deflects the flight path, or at least tries. If the flight path is straight, the only "g" is gravity. If it's an upward curve, like entering a loop, "g's" are the sum of gravity and centrifugal force. At the bottom, they add; floating over the top, gravity is subtracted. So, "g" force depends on the orientation of gravity. A banked turn is a loop in an oblique plane where the gravitational offset against centrifugal force is established by trigonometry.
Absolute drivel. Centrifugal force is fictitious. Increasing the AOA (until the stall) primarily increases the lift. This primarily just makes you go up. The force generated by the wing however doesn't necessarily just act to counter gravity. If it's canted backward, it is induced drag. If the wings are banked, the airplane will move in the direction of the bank.

However that alone isn't enough to make a plane turn (or loop). It would be like helicopter translating sideways. The thrust from the propeller, the streamlining of the fuselage, and the tail of the aircraft also rotate the aircraft into the turn. If you do this such that the axis of the plane is following the turn, we call this coordinated flight.

In a steep bank, the tail on a Cessna 172 at slow speeds is way out back behind the CG which is tangent to the turn's flight path.
Again you've lost me. In every 172 I've flown in, the tail remains in the same place regardless of the airspeed or amount of bank.
 
An interesting tidbit on the 1940's Ercoupe . . . it was designed with limited aft aileron to prevent stalling.
 
Mr. Swave, I think a lot of these questions could be resolved if you grabbed an instructor and tried a few stalls. Meanwhile, try to visualize the angle of attack. You'll have it right when the horizon doesn't matter. AoA is the angle between wing chord and your 3D velocity.
 
You lost me there. The nose drops and increases AOA?
An extreme example would be a whip stall.


Centrifugal force is fictitious.
"That which we call a rose
By any other name would smell as sweet." Shakespeare

Increasing the AOA (until the stall) primarily increases the lift. This primarily just makes you go up. ... If the wings are banked, the airplane will move in the direction of the bank.
I can bank left, yet turn right. It takes more lift to go down than go up--due to the upward component of thrust. You can enter a stall maintaining straight and level flight at a constant weight and increasing angle of attack, but have no increase in lift--it's still just enough to balance weight (or less due to the upward component of thrust).

In every 172 I've flown in, the tail remains in the same place regardless of the airspeed or amount of bank.
The CG is at the end of the turn's radius. The tail (and spinner) are not. The tail goes around like a telephone pole sticking out of the bed of your truck. A flag on the end would be blown to the inside of the turn. Since the tail surfaces are canted, that means the relative wind is coming from underneath, decreasing the AoA (authority) of the horizontal stabilizer/elevator.

dtuuri
 
You lost me there. The nose drops and increases AOA?

Pilots tend to think that lift pretty much falls to zero when the wing stalls but if you look at a typical trainer coefficient of lift vs AoA curve you'll see that the C of L barely drops as the AoA increases slightly beyond the critical AoA. What actually happens that creates that "bottom dropping out" feeling is that when the wing stalls the slight decrease in wing lift causes the lift to be less than what's needed to offset the airplane's weight and as the wing drops, the AoA is increased because the direction of the relative wind shifts due to the wings downward motion.
 
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